[codility] FrogJmp

app.codility.com/programmers/lessons/3-time_complexity/frog_jmp/

FrogJmp coding task - Learn to Code - Codility

나머지가 0보다 크면 1을 더해줌

def solution(X, Y, D):
    # write your code in Python 3.6
    q = (Y-X)//D 
    r = (Y-X)%D
    return q if r == 0 else q+1